Math, asked by Geethika9511, 10 months ago

Two bags together contained 50 chocolates .from the first bag,12 chocolates were given to a child . Then eight chocolates were taken from the first bag and put into the second bag to make the number of chocolates equal in both bag. How many chocolates were originally there in each bag?

Answers

Answered by varun1235
4
previously there were 25 chocolates in each bag.

Bag 1 =25-12-8=5

Bag 2 =25+8=33

here is your ans
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