Question

two bags were sold for rupees 500 each .the shopkeeper made a loss of 10 % on the first and a profit of 8% on the other . Find his total gain or loss percent in the whole tranction​

Answer 1

Answer:

Cost price of a T.V set =Rs 10000 

profit =10%

Selling price =[100+p/100]×C.P

=[100+10/100]×10000

=110/100×10000

=11×1000

=Rs. 11000

Loss =10%

Selling price =[100−L/100]×C.P

=100−10/100×10000

=90/100×10000

=9×1000

=9000

Total cost price =10000+10000 =20000

Total selling price =11000+9000=20000

Here C.P=S.P

Therefore, it is neither Loss nor Profit.

Answer 2

Step-by-step explanation:

first case

SP of the bag = Rs.500

loss = 10%

CP = ?

$cp \: of \: the \: first \: bag \: = sp \times \frac{100}{100 - loss\%}$

$= 500 \times \frac{100}{100 - 10}$

$= 500 \times \frac{100}{90}$

$= \frac{5000}{9}$

second case

SP = Rs. 500

profit = 8%

CP of the second bag = ?

$cp \: of \: the \: 2nd \: bag \: = sp \times \frac{100}{100 + profit\%}$

$= 500 \times \frac{100}{100 + 8}$

$= 500 \times \frac{100}{108}$

$= \frac{12500}{27}$

Now total CP of two bags

$= \frac{5000}{9} + \frac{12500}{27}$

$= \frac{15000 + 12500}{27}$

$= \frac{27500}{27}$

$= 1018 \frac{14}{27}$

Total SP = Rs. 500 + Rs. 500

= Rs. 1000

Here CP< SP

So there is loss

$total \: loss = 1018 \frac{14}{27} - 1000$

$= 18 \frac{14}{27}$

$loss = \frac{18 \frac{14}{27} }{1018 \frac{14}{27} } \times 100\%$

$= \frac{ \frac{500}{27} }{ \frac{2750</p><p></p><p>0}{27} }$

$= \frac{500}{27} \times \frac{27}{27500} \times 100\%$

$= \frac{100}{55} \%$

$= \frac{20}{11} \%$

$= 1 \frac{9}{11} \%$

$so \: loss \: percent = 1 \frac{9}{11} \%$