Two balanced dice are rolled. find the probability that the sum of numbers on two dice is a multiple of 6
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Answered by
3
probability = favorable outcomes/possibly outcomes
here,
favourable out comes= 5
possible outcome = 36
probability = 5/36
Answered by
1
Possible outcomes
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Probability= no of favourable outcomes / no of all possible outcomes
= 6/36 = 1/6 = 0.16
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