Question

Two balanced dice are tossed together. Then ......... is the probability of an event that sum of integers

obtained on dice is less than 7.​

Answer 1

Answer:

(1,1),(1,2),(2,1),(1,3),(3,1),(2,2),(1,4),(4,1),(2,3),(3,2),(1,5),(5,2),(2,4),(5,2),(2,4),(4,2),(3,2),(4,4),(5,5),(6,6)

total = 18

probability= 18\36

=1/2 (answer)

Answer 2

Answer:

No.of all possible outcome is 36

let A be the event that the sum of Integers obtained on dice is less than 7

outcome favourable to event A=15

p(A)=outcome favourable to event A/no.of all possible outcome

p(A)= 15/36

p(A)=5/12