Question

two ball are dropped from the same point after an interval of 1 sec .if acceleration due to gravity is 10m/s^.the separation between the balls,3 second after release of first ball is --------?​

Answer 1

answer:

25 meters

explanation:

first ball travel for 3 sec

so distance traveled is = 1/2at^2

d1= 1/2×10×3^2

=5×9=45 mts

second ball travel for 2 sec

so d2=1/2at^2

=1/2×10×2^2

=20mts

so d1-d2=25mts