Question

Two balls A and B are pushed horizontally from a table of height 3m. Ball A is pushed so that

its initial velocity is 10 m/sec and ball B is pushed so that its initial velocity is 15 m/sec. What

is the difference in the distance between the points of impact of the two balls on the ground:

(g = 9.8 m/sec)

Answer 1

Explanation:

Time for both balls to hit the ground = √(2h/g)

= √0.6

Distance travelled = v t = v √0.6

A = 10√0.6

B = 15√0.6

Difference = B-A = 5√0.6