Question

two balls A and B are simultaneously thrown a is thrown from ground level with a velocity of 20 metre per second in the upward direction and b is thrown from a height of 40 m in the downward direction with same velocity where will the two balls meet​

Answer 1

Answer:

from the top, this distance will be equal to the distance travelled by the ball thrown at 20m/s in 1 second, or, it will be equal to (20)(1) + (1/2)(g)(1^2) = 20 + 4.9 = 24.9 metres. or, from the bottom, (40 - 24.9) metres, which is equal to 15.1 metres.