Question

Two balls A and B are thrown vertically upward with velocities 5 m/s and 10 m/s respectively. Find separation between them after 1 second.

Answer 1

Answer:

5m

Explanation:

total distance traveled by ball A in one second = 5m

total distance traveled by ball B in one second = 10m

the total separation between them after 1 second =10m-5m

=5m

Answer 2

Answer:

so the separation between them after 1 sec is 5m .

Explanation:

it given that ball A covers 5 m in 1 sec and ball B covers 10 m in 1 sec .

so after 1 sec

ball A is 5 m apart from its initial position

ball B is 10 m apart from its initial position

its figure look like this

ball A : (u) ----- 5m -----(v)

ball B : (u) -------------- 10m ----------------(v)

so to find separation between them we have to find the their difference

10m - 5 m = 5 m