Two balls A and B are thrown vertically upwards with speed 10m/s and 20m/s respectively. What is the ratio of their displacement travelled in the last secon of their upward motion.
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Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at
2
=20(2)+0.5(−10)(2)
2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at
2
45=0+0.5(10)(t)
2t ′=3sTotal time= 3+2= 5s.
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