Two balls A and B have masses m and 2m and velocities v and 2v respectively.what is the ratio of momentum of A to that of B?
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Answer:
1:2
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Let p1 = m1v1 => p1 = my and p2 = m2v2 => (2m)(2v)
Therefore p1/p2 = m1v1/ m2v2
p1/p2 = me/2m(2v)
p1/p2 = mv/4mv
p1/p2 = 1/4
Therefore ratio of momentum is 1:4
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Therefore p1/p2 = m1v1/ m2v2
p1/p2 = me/2m(2v)
p1/p2 = mv/4mv
p1/p2 = 1/4
Therefore ratio of momentum is 1:4
Hope you like it and don’t forget to mark me the brainliest
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