Question

Two balls A and B of mass 'm' and '2m' are in motion with velociries '2v' and 'v' respectively. Compare
1. Their inertia
2. Their momentum
3. The force needed to stop them in same time

Answer 1

Given:
Two balls A and B of mass m and 2m
Initial velocity of first ball =2V
Initial velocity of second ball= V
1)Compare inertia:
As inertia is measure of mass. Hence the object with greater mass has more mass.
So, Ball B is having more inertia.
2)Compare momentum:
Momentum is the product of mad and velocity.
P= mxv
So Pa=mx2v=2mv
Pb=2mxv=2mv
So, momentum in both the cases are same.

3)The force needed to stop them in same time:
From Newton's second law:
F= dp/dt
= change in monentum/dt
= 0-2mv/time
As momentum is same for given time , so same force is required to stop them.

Answer 2

Explanation:

Given:

Two balls A and B of mass m and 2m

The initial velocity of the first ball =2V

The initial velocity of the second ball= V

1)Compare inertia:

Inertia is a measure of mass. Hence the object with greater mass has more mass.

So, Ball B is having more inertia.

2)Compare momentum:

Momentum is the product of mad and velocity.

P= M x V

So Pa= m x 2v =2mv

Pb=2m x v=2mv

So, the momentum in both cases Is the same.

3)The force needed to stop them at the same time:

From Newton's second law:

F= dp/dt

= change in monentum/dt

= 0-2mv/time

As momentum is the same for the given time, so same force is required to stop them.