Question

two balls A and B of masses 100g and 250g are connected by a streched spring of negligible mass placed on a smooth table when the balls are realeased simultaneously the initial acceleration of A is 10cm/s2 westward the magnitude of acceleration of B is

Answer 1

"You can simply use the formula of F = mass * acceleration. Since, the force is working in equal and opposite direction, they will be equal. Hence,

m1a1 = m2a2

Since both, the weight are connected to a single string with equal force,

100 * 10 = 250 * a2

a2 = 1000/250

a2 4 cm/s^2

since the terms are in g hence you don’t have to change the unit of acceleration.

"