Physics, asked by Deppak4131, 1 year ago

Two balls a and b of masses 100g and 250g connected to the ends of a weightless stretched spring are placed on a smooth horizontal surface .on being released the ball b goes towards west with an initial acceleration of 10cm/s^2. with what initial acceleration and in which direction will the ball a go?

Answers

Answered by aristocles
93

For block B we can say

F_b = m_b * a

given that

m_b = 250g = 0.250 kg

a = 10 m/s^2

now by above formula

F = ma = 0.250 * 10 = 2.50 N

now we know that both blocks are connected by same spring

So spring force will be same on both blocks

so force block "A" the spring force will be same

F = ma

2.5 = m_a * a

given that

m_a = 100g = 0.100 kg

now by above equation

2.5 = 0.100 * a

solving above equation

a = 25 m/s^2

so acceleration of block "a" is 25 m/s^2 towards EAST


arpitvrock227: How can we answer for the direction of A?
Answered by prakashk3496
9

Answer:

Explanation:

For block B we can say

given that

now by above formula

now we know that both blocks are connected by same spring

So spring force will be same on both blocks

so force block "A" the spring force will be same

given that

now by above equation

solving above equation

so acceleration of block "a" is 25 m/s^2 towards EAST

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