two balls a and b of same masses are thrown from the top of a building. a is thrown upwards with velocity v and b is thrown downwards with velocity v, then
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Answer:
If h is the height of the building, then v2A = v2 + 2gh and v2B = (- v)2 + 2gh. Clearly vA = vB
Explanation:
Both strike the ground with same velocity. Explanation: let the velocity of a(thrown up) be v, when it comes back to the height of the building, it's velocity will be v in the downward direction (which is the same way B was thrown), so they both will hit the ground with same velocity but at different times.
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