Two balls are drawn at random, with replacement from a box containing 9 black and 7 white balls. Calculate the probability of both balls are black.
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Total balls 17
P of getting black balls
9/ 17
P of getting white balls
7/ 17
If Right plz mark me as Brainliest
P of getting black balls
9/ 17
P of getting white balls
7/ 17
If Right plz mark me as Brainliest
UnknownDude:
No, bud
The probability of 1 ball being black is 9/16
What's asked is the probability of 2 black balls.
And total balls = 16, not 17
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Here's your answer...
The total ways of selecting two balls from 16 (or selecting one ball in two turns, with replacement) is C(16,2).
The number of ways of selecting two black balls is C(9,2).
Thus, probability = C(9,2)÷C(16,2)
= (9×8)/2 ÷ (16×15)/2
= 3/10
The probability of choosing two black balls from 16 balls is 0.3
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Here's your answer...
The total ways of selecting two balls from 16 (or selecting one ball in two turns, with replacement) is C(16,2).
The number of ways of selecting two black balls is C(9,2).
Thus, probability = C(9,2)÷C(16,2)
= (9×8)/2 ÷ (16×15)/2
= 3/10
The probability of choosing two black balls from 16 balls is 0.3
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