two balls are drawn in succession without replacement from a plastic container,5 red balls and 6 blue balls.Let Z be the random variable representing the number of blue balls.
1. determine the sample space?
2. what are the possible values of random variable Z?
3. construct the probability distribution table of the random variable Z?
Answers
Answer:
SOLUTION: Two balls are drawn in succession without replacement from a box containing 4 red balls and 6 blue balls. Let Z be the random variable representing the number of blue balls. Constr
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Question 1101386: Two balls are drawn in succession without replacement from a box containing 4 red balls and 6 blue balls. Let Z be the random variable representing the number of blue balls. Construct the probability distribution of the random variable Z.
Answer by Edwin McCravy(18411) (Show Source): You can put this solution on YOUR website!
First determine the probabilities of the events.
events Probability
RR (4/10)(3/9) = 2/15
RB (4/10)(6/9) = 4/15
BR (6/10)(4/9) = 4/15
BB (6/10)(5/9) = 1/3
The probability of 0 blue balls (RR)is 2/15
The probability of 1 blue ball is (RB or BR) is 4/15+4/15 = 8/15
The probability of 2 blue balls (BB) is 1/3
So the probability distribution is:
Z p(Z)
--------
0 2/15
1 8/15
2 1/3
Notice that the sum of the probabilities = 2/15+8/15+1/3 = 1
Edwin
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