Question

Two balls are droped from same height at 1 second interval of time. The separation between
the two balls after 3 second of the drop of the 1st ball is _________
​

Answer 1

Answer:

24.5m

Explanation:

As balls are dropped ,

u = 0

a = +g = 9.8

For 1st Ball

time = 3 seconds

Using , s = ut + 1/2at^2

S= 1/2 × 9.8 × 3 × 3

S = 44.1m

For 2nd Ball ,

time = 2 seconds

s = 1/2 × 9.8 × 2 ×2

s = 19.6 m

Separation = 44.1-19.6 = 24.5m