Two balls are dropped from heights at different instants.Second ball is dropped 2sec after the first ball.If both balls reach the ground simultaneously after 5sec of dropping the first ball,then the difference between the initial heights of the two balls will be:1. 58.8m2. 78.4m3. 98m4. 117.6m
Answers
Answered by
196
Given two balls are dropped from heights and we should calculate the initials heights.
For 1st ball :
S = ut + 1/2 gt^2
= 0 + 1/2 * g (5)^2
= 25g/2 --------------------------- h1
For 2nd ball
S = ut + 1/2 gt^2
= 0 + 1/2 * g * (3)^2
= 9g/2 -------------------------- h2
Now, we should find out the difference between the initials heights :
h1 - h2 = 25g/2 - 9g/2
= 16g/2
= 8g
= 8 * 9.8
= 78.4m.
The answer is option(2).
For 1st ball :
S = ut + 1/2 gt^2
= 0 + 1/2 * g (5)^2
= 25g/2 --------------------------- h1
For 2nd ball
S = ut + 1/2 gt^2
= 0 + 1/2 * g * (3)^2
= 9g/2 -------------------------- h2
Now, we should find out the difference between the initials heights :
h1 - h2 = 25g/2 - 9g/2
= 16g/2
= 8g
= 8 * 9.8
= 78.4m.
The answer is option(2).
Answered by
5
Answer:
78.5
Explanation:
option 2 is the answer
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