Question

Two balls are dropped from same height at 1 second interval of time

Answer 1

The Original Question is:

Two balls are dropped from same height at 1 second interval of time. The separation between the two balls after 3 seconds of the drop of first ball is?

And the Answer is:

Distance travelled by the 1st ball after 3 sec

S1= 1/2gt^2

=1/2*10*9

=45m

Distance travelled by the 2nd ball after 2sec

S2= 1/2gt^2

=1/2*10*4

=20m

Distance between the balls after the 1st ball travel for 3sec

D=S1-S2

=45m-20m

=25m

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Answer 2

Answer:

correct answer is 25 m

Step-by-step explanation:

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