Question

Two balls are dropped from same height h one on a smooth plane and other on a rough plane

Answer 1

A: as always with questions of kinematics of constant acceleration, we refer to the four principal kinematic equations:

We are interested in distances d, and we separate the distance into horizontal and vertical components:

Horizontal: d = 50*t (this is also the value of the (-) vertical displacement of the plane)

Vertical : d = -1/2*10*t^2

The contact point occurs when -5*t^2 = - 50*t , so t = 10 seconds.

The horizontal distance after 10 seconds is 500 meters

The vertical distance after 10 seconds is 500 meters, hence the slope distance is

sqrt (2*500^2) = 707 meters (for g = 10 m/s^2)