Question

Two balls are projected at an angle of θ and (90-θ) to the horizontal with same speed . The ratio of their maximum vertical heights is
(1 Point)

a) 1: 1

b) tan θ: 1

c) 1 : tan θ

d) tan ^2 θ : 1 use​

Answer 1

Correct option is

D

tan2θ : 1

H1 = 2gu2sin2θ-----(i)

H2 = 2gu2sin2(90−θ)=2gu2cos2θ----(ii)

Divide (i) by (ii), we get

H2H1= 1tan2θ

Answer 2

Explanation:

$\large{\blue{ \frac{H_1}{H_2}= \frac{ \frac{{u}^{2} { \sin }^{2}θ }{2g}}{ \frac{{u}^{2} { \sin }^{2}(90-θ )}{2g}} }} \\ \large{\blue{ \frac{H_1}{H_2}= \frac{ { \sin }^{2}θ }{ { \sin }^{2}(90-θ )} }} \\ \large{\blue{ \frac{H_1}{H_2}= \frac{ { \sin }^{2}θ }{ { \cos }^{2}θ } }} \\ \large{\blue{ \frac{H_1}{H_2}= \frac{ {\tan}^{2}θ }{1} }} \\ \large{\blue{H_1 : H_2}} \\ \large{\blue{{\tan}^{2} θ : 1}}</p><p>$

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