Question

two balls are projected simultaneously with the same velocity 'u' from the top of the tower,one vertically upwards and the other vertically downwards. their respective times at the journey are t1and t2. find the ratio of the time​

Answer 1

Answer:

Two balls are projected simultaneously with the same velocity 'u' from the top of the tower,one vertically upwards and the other vertically downwards. their respective times at the journey are t1and t2. The ration of the time is 1:1

Explanation:

when one of the ball is thrown  upward after achieving the highest height its velocity will be zero

For the acceleration g the ball will have the same velocity u at the same height.

It is same for the second ball also.  

As the velocity in both the cases will be same on ground

Hence the ratio will be 1:1.

Answer 2

Answer: 1:1

Explanation:

the answer is very simple both balls have same velocity at the time of reaching the ground so ratio is 1:1 first ball is projected with velocity u upward when it reaches its intial postion its velocity is same u with eqation

v2-u2=2as where s=0 displacement so v2=u2

v=u from height the velocity is u downword it is the same condition of second ball