Question

Two balls are projected simultaneously with the same speed from the top of a tower, one vertically upwards and the other vertically downwards. They reach the ground is 9 s and 4 s, respectively. The height of the tower is (g = 10 m/s)​

Answer 1

Answer:

Explanation:

Height of building is

V=u+at

V=10m/s²*(9-4/2s)

V=10m/s²*2.5s

V=25m/s

To find height

Ut+1/2at⅔

25m/s*4s+1/2*10m/s²*16s²

180m

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