Two balls are thrown horizontally from the top of a
building with speed u, and un respectively in
opposite directions. The separation between two
balls when they are moving perpendicular to each
other, is (Acceleration due to gravity is g)
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Answer:
General velocity vector of the projectiles is given by
V=v1+j(gt)...................(1)
V=v2+j(gt).............(2)
for both the vectors above to be perpendicular ,their dot product must be zero.
hence,dot product is
v1×v2+g2t2=0
finally,
t=gv1v2
⁹
Explanation:
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