two balls are thrown vertically upwards with their initial speeds in the 1:2.Find the ratio of their maximum heights
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36
Answer:
1:4
Explanation:
At the maximum height, velocity = 0.
consider that as final point, final velocity = v = 0.
As it has gone vertically upwards, opposite to gravity, acceleration = - g.
Using eqs. of motion:
⇒ v^2 = u^2 + 2aS
⇒ 0^2 = u^2 + 2(-g)S
⇒ u^2 = 2gS
⇒ u = √2gS
Now, for each ball, let the initial velocities and heights be u₁, u₂ and S₁, S₂.
Ratio = 1:2
u₁ : u₂ = 1:2
√2gS₁ : √2gS₂ = 1:2
2gS₁ : 2gS₂ = 1² : 2² {square on both sides}
S₁ : S₂ = 1 : 4
Ratio of maximum heights is 1:4
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Answer:
The above picture will help you.
Sorry., My previous answer was wrong..❤️❤️
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