Two balls of different masses are thrown vertically upward with same initial velocity. Maximum heights attained by them are h1 and h2 respectively. What is h1/h2
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We can find the height using the third equation of motion. v²-u²=2as Height 's' depends on initial and final velocity.The height will be same.So h1/h2 is 1
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Hey there !!
At the maximum height final velocities of the object will become zero.
So maximum height =u²/2g as both have same initial velocities ratio of maximum heights attained is 1.
Hope this helped u !!
At the maximum height final velocities of the object will become zero.
So maximum height =u²/2g as both have same initial velocities ratio of maximum heights attained is 1.
Hope this helped u !!
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