Question

Two balls of different masses have same K.E which ball (lighter or heavier) will passess greater momentum

Answer 1

actually the momentum of heavier ball will be greater
first find the relation between the velocity

m1>m2 then

$1 \div 2m1 {v1 }^{2} = 1 \div 2m2 {v2}^{2}$
from this v1<v2

now in the same formula taking m1v1 as p1(momentum) and m2v2 as p2

p1v1=p2v2

here v1<v2 therefore p1>p2...