two balls of different masses one lighter and the other heavier are thrown vertically upwards with the same initial speed.which one will rise to the great height ?
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Because we know- v^2 = u^2 + 2*a*s ….here v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance covered.
From this it is clear that the distance moved by a body while accelerating/decelerating from an initial velocity u to a final velocity v is NOT dependent on its mass.
In cases of vertical projection as the one mentioned in the question, the acceleration due to gravity is the cause of deceleration/retardation of the balls shot upwards with some velocity. As a result, the balls slow down and their velocity becomes zero at the maximum height. So our equation becomes-
(0)^2 = u^2 - 2*g*s [as final velocity is 0 & acceleration is -g]
=> s = (u^2)/2g
As values of u and g will be same for both the balls, so they will share the same value of s too and hence, they will rise to the same height.
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From this it is clear that the distance moved by a body while accelerating/decelerating from an initial velocity u to a final velocity v is NOT dependent on its mass.
In cases of vertical projection as the one mentioned in the question, the acceleration due to gravity is the cause of deceleration/retardation of the balls shot upwards with some velocity. As a result, the balls slow down and their velocity becomes zero at the maximum height. So our equation becomes-
(0)^2 = u^2 - 2*g*s [as final velocity is 0 & acceleration is -g]
=> s = (u^2)/2g
As values of u and g will be same for both the balls, so they will share the same value of s too and hence, they will rise to the same height.
plz mark me brainliest
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