Two balls of equal mass have a head on collision with speed 6 m/s. If the coefficient of restitution is 1/3, the velocity of each ball after impact will be
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The speed of the balls will be same after collision
relative velocity of approach is 6-(-6)=12m/s., coefficient of restitution is 1/3
put this in the above equation,
you will get relative velocity of separation=4m/s
as the balls will move in opposite direction after collision, the velocity of one ball will be 2m/s and -2m/s for other. (i.e relative velocity=2-(-2)=4m/s)
hence speed of each ball will be 2m/s
relative velocity of approach is 6-(-6)=12m/s., coefficient of restitution is 1/3
put this in the above equation,
you will get relative velocity of separation=4m/s
as the balls will move in opposite direction after collision, the velocity of one ball will be 2m/s and -2m/s for other. (i.e relative velocity=2-(-2)=4m/s)
hence speed of each ball will be 2m/s
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e=v2-v1/u1-u2 ;
v2=v1;
And after much solving answer is 2m/s.
v2=v1;
And after much solving answer is 2m/s.
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