Question

Two balls of equal masses m each undergo oblique collision

Answer 1

Explanation:

where is the complete question

Answer 2

Two balls of equal masses m each undergo oblique collision. If collision is perfectly elastic, then angle between their velocities after collision is

(1)π/4

(2)π/3

(3)π/6

(4)π/2

Answer:

The angle between their velocities after collision is  π/2.

Explanation:

The kinetic energy will be conserved because it has an elastic collision.  

                            $\frac{1}{2} mv_{1}^2 + \frac{1}{2} mv_{2}^2 = \frac{1}{2} mu_{1}^2 + \frac{1}{2} mu_{2}^2$

                                            $v_{1}^2 + v_{2}^2 = u^2$

                                     $V_{1}$ cosθ + $V_{2}$ cos ɸ = u

                                        cosθ= $(\frac{v_{1}}{v_{2}})(\frac{sin^2\theta} {cos\phi})$

                                          cos(ɸ + θ) = 0

                                           ⇒ (ɸ + θ) = 90

Which is equal to π/2.

Hence for the given question, The angle between their velocities after collision is  π/2.

To know more;

Two balls of equal masses m each undergo oblique collision. If collision is perfectly elastic, then angle between their velocities after collision is

(1)π/4  

(2)π/3

(3)π/6

(4)π/2

https://brainly.in/question/1727900