Question

Two balls of mass m each are raised to heights √2h and 2h respectively. Find out the ratios of their potential energies

Answer 1

Hey mate......☺☺☺

Here is your answer⤵⤵⤵⤵⤵

⏩Potential energy of the first ball = mgh = m× 10 × √2 h =10√2mh

⏩ Potential energy of the second ball = mgh = m ×10 ×2h =20mh

⏩ Therefore, required ratio =
$(10 \sqrt{2} ) \div 20 = 1 \div \sqrt{2}$


❤❤❤Hope it will help you❤❤

❤❤❤Thanks❤❤❤

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