Two balls of mass m1 and m2 are separated by a distance d. How much the force between the two balls change if the distance
between them is increased 5times. Solve
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18
Answer:-
Given:
mass of one ball (M) = m₁
mass of other ball (m) = m₂
Distance between them (r) = d.
We know that,
Gravitational force (F) = GMm/r²
(G is gravitational constant).
So,
F = Gm₁m₂/d² -- equation (1)
Now,
we have to find,
gravitational force if distance between them becomes 5 times.
→ new distance between them = 5d.
So, new gravitational force (F') = Gm₁m₂ / (5d)²
⟶ F' = Gm₁m₂ / 25d²
⟶ F' = (1/25) * (Gm₁m₂ / d²)
⟶ F' = F/25
[ from equation (1) ]
∴ The gravitational force between them reduces by 25 times the original force between them.
Answered by
1
Given:
There are two balls:
- mass of one ball (M) = m₁
- mass of other ball (m) = m₂
- Distance between them (r) = d.
We know that,
- Gravitational force (F) = GMm/r²
(G is gravitational constant).
So,
- F = Gm₁m₂/d² -- equation (1)
Now,
To find:-
- gravitational force if distance between them becomes 5 times.
→ new distance between them = 5d.
- So, new gravitational force (F') = Gm₁m₂ / (5d)²
⟶ F' = Gm₁m₂ / 25d²
⟶ F' = (1/25) * (Gm₁m₂ / d²)
⟶ F' = F/25
[ from equation (1) ]
- ∴ The gravitational force between them reduces by 25 times the original force between them.
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