Two balls of mass ratio 1 : 2 are dropped from the same height.
(i) State the ratio between their velocities when they strike the ground and
(ii) the ratio of the forces acting on them during motion.
Plz answer briefly......
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m1=x and m2 = x2
kinetic energy ko conserve kro
1/2m1v1²=1/2m2v2²
v1² /v2²=m2/m1
(v1/v2)²=2
v1:v2=√2:1 ans
and now take force force isme momentum ke threw lge ga
force mg lge ga
then m1g=m2g
x=2x
1:2
kinetic energy ko conserve kro
1/2m1v1²=1/2m2v2²
v1² /v2²=m2/m1
(v1/v2)²=2
v1:v2=√2:1 ans
and now take force force isme momentum ke threw lge ga
force mg lge ga
then m1g=m2g
x=2x
1:2
mimansh:
good explanation but the first ans is 1:1
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