two balls of masses 2kg and 4kg are projected with initial velocity 1m/s and 2m/s respectively. What is the time for which first time the height of centre of mass in metres will be greater than its velocity in m/s(Take g=10m/s)
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Answer:
11th
Physics
Work, Energy and Power
Collisions in Two Dimensions
Two balls of masses 2 kg an...
PHYSICS
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Asked on December 27, 2019 by
Yuna Sagani
Two balls of masses 2 kg and 4 kg are moved towards each other with velocities 4m/s and 2m/s, respectively, on a frictionless surface. After colliding, the 2 kg ball returns back with velocity 2m/s. Then find
a) velocity of the 4 kg ball after collision
b) coefficient of deformation e
c) impulse of deformation J
d
d) Maximum potential energy of deformation
e) impulse of reformation
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ANSWER
a) By momentum conservation,
2(4)−4(2)=2(−2)+4(ν
2
)
⟹ν
2
=1m/s.
b) e=
Velocityofapproach
Velocityofseparation
=
4−(−2)
1−9−2)
=
6
3
=0.5
c) At the maximum deformed state, by conservation of momentum, common velocity is ν=0
J
D
=m
2
(ν−u
2
)=4[(0−(−2)]=8Ns
d) Potential energy at the maximum deformed state,
U= loss in kinetic energy during defirmation
or U=(
2
1
m
1
u
1
2
+
2
1
m
2
u
2
2
)−
2
1
(m
1
+m
2
)ν
2
=(
2
1
2(4)
2
+
2
1
4(2)
2
)−
2
1
(2+4)(0)
2
=24J
e) J
R
=m
2
(ν
2
−ν)=4(1−0)=4Ns
also J
R
=eJ
D
=0.5×8=4Ns
Explanation:
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