Question

Two balls of masses 3 and 4M are inmotion
with velocities 6v and 8v respectively. Their
nomentum is in the ration)
Ws-​

Answer 1

Answer:

The momenta are in the ratio 9:16.

Given,

m1= 3M, v1= 6v.

Therefore momentum (p1) =mv=18Mv.

m2=4M, v2=8v

Momentum (p2)= 32Mv.

Ratio=18/32=9/16.