Two balls of masses 3 and 4M are inmotion
with velocities 6v and 8v respectively. Their
nomentum is in the ration)
Ws-
Answers
Answered by
0
Answer:
The momenta are in the ratio 9:16.
Given,
m1= 3M, v1= 6v.
Therefore momentum (p1) =mv=18Mv.
m2=4M, v2=8v
Momentum (p2)= 32Mv.
Ratio=18/32=9/16.
Similar questions