Question

two balls of masses M1 and M2 are moving with velocities one metre per second and 3 metre per second respectively in the opposite direction of the bodies undergo one dimensional elastic collision the body of mass M1 comes to rest and find the ratio of M1 and M2 ​

Answer 1

Answer:

yes its good..

Explanation:

initial velcty v1 is zero and v2 of both mamsses are zero

as by using law of conservation of momntum

m1v1+m2v2=m1primev1prime+m2v2(prime)

as v1 and v2 are at rest so

0=m1v1+m2v2(prime) no sepate them like

m1v1(prmi)=m2v2(prime)

now divide them like

V1/v2 equals m2 ovee m1 prime

Answer 2

Answer:

7:1

Explanation:

u_(1) 1m//s, u_(2) = -3m//s,v_(1) = 0`

`v_(1) =((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1) +((2m_(2))/(m_(1)+m_(2)))u_(2)`

`0 =((m_(1) -m_(2))/(m_(1)+m_(2)))1+ ((2m_(2))/(m_(1)+m_(2))) (-3)`

`m_(1)-m_(2)=6m_(2) ,m_(1) =7m_(2), (m_(1))/(m_(2)) = (7)/(1)`.