Two balls of same mass 100g each 1 was made up of mud another was pith ball at a incident both fall from height 10m,if the reaction time for the both ball is 0.5 second. Mud ball stitch with ground whether pith ball rebounce back with velocity of 2m/s then,calculate force applied by the each ball to the ground.Take gravity 10m/s.
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Answer:
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A
5I1=6I2
Velocity before strike is u=29h
I
bounces to h/4
so velocity after bouncing was ins
given by 4h=29v2
⇒V=29h=2u
chance in velocity =−2u−u
= final - initial.
final taken as -ve because
direction changed.
so chores in momentum △P=M△V=−23mu
impulse =F△t=△P=2−3mu=I1
II ball u=29u
bonces to h/16⇒10h=29v2
⇒v=429h=4u
⇒△v=
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