Question

Two balls of same mass and identical in shape and size are allowed to fall from two different height 16 m and 64 M then the ratio of their Momentum just before striking the ground is

Answer 1

Answer:

Velocity before strike is u=29h

I 

bounces to h/4

so velocity after bouncing was ins

given by 4h=29v2

⇒V=29h=2u

chance in velocity =−2u−u

= final - initial.

final taken as -ve because

direction changed.

so chores in momentum △P=M△V=−23mu

impulse =F△t=△P=2−3mu=I1

II ball u=29u

bonces to h/16⇒10h=29v2

⇒v=429h=4u

⇒△v=4−u−u=4−5u