Question

Two balls of same mass and identical in shape and size are allowed to fall from two different height 16 m and 64 M then the ratio of their Momentum just before striking the ground is

Answer 1

$\tt{Answer}$

To find

ratio of momentum, it’s required to find their velocities.

To find velocities, apply conservation of energy.

For first ball,

m1gH1 = 1/2 m1 v1^2

Square root (2gH1) = v1…………..(1)

Similarly for second ball ,

Squareroot (2gH2) = v2…………..(2)

Ratio of momentum,

P1/P2 = m1v1/m2v2

=squareroot(2gH1)/ squareroot (2gH2)

(Mass of both balls same (given ) I.e. m1=m2)

= squareroot(2*g*16)/squareroot(2*g*64)

=4/8

=1/2

P1/P2 =1/2

This suggests that mass fallen from higher height has more momentum than other.

Answer 2

Answer:

hope it helps you plz me

Explanation:

ratio of momentum, it’s required to find their velocities.

To find velocities, apply conservation of energy.

For first ball,

m1gH1 = 1/2 m1 v1^2

Square root (2gH1) = v1…………..(1)

Similarly for second ball ,

Squareroot (2gH2) = v2…………..(2)

Ratio of momentum,

P1/P2 = m1v1/m2v2

=squareroot(2gH1)/ squareroot (2gH2)

(Mass of both balls same (given ) I.e. m1=m2)

= squareroot(2*g*16)/squareroot(2*g*64)

=4/8

=1/2

P1/P2 =1/2

This suggests that mass fallen from higher height has more momentum than other.