Question

Two balls of same mass are thrown horizontally from the top of a tower in the opposite directiin with velocities 3 m/s and 4 m/s. The distance between the balls, when their velocities are mutually perpendicular will be nearest to

Answer 1

Answer:

The distance between two balls the 2.45 m

Explanation:

According to the problem two ball have the same mass

the velocity of the ball 1 is v1= 3m/s

and the velocity of the ball v2= 4m/s

now two balls are going opposite direction

Therefore at time t the velocity of ball 1is

v1= 3i+gtj      v2= -4i+gtj

Now as said if the angle between them is 90 degree

Then, v1.v2= 0

       or, -12+gt^2= 0 [ g= 10 m/s]

      or t = √12/g

              =  0.35 s

V= v1- v2

 therefore the distance between them at time 0.35s

V x t

= 7m/s x 0.35

= 2.45m