Two balls of same mass are thrown horizontally from the top of a tower in the opposite direction
with velocities 3 m/s and 4 m/s. The distance between the balls, when their velocities are mutually
perpendicular will be nearest to ?
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Answer:
please mark this as brain list answer....
Explanation:
v1=3i-gtj
v2=-4i-gtj
v1.v2=0 for 90 deg
=>-12+g^2t^2=0
=>gt=root12
=>t=root(12) /10
=>dis = 7 *root(12)/10
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