two balls P and Q having masses 2Kg and 4kg respective are dropped from the same height simultaneously. Show that they will reach the ground simultaneously
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Solution : Since we know that,
F = GMm/R²
And F = mg
mg = GMm/R²
g = GM/R²
For Earth, M = 6 × 10²⁴ and R = 6.4 × 10^6.
g = ( 6.67 × 10^(-11) × 6 × 10²⁴ )/[ 6.4 × 10^6 ]²
g = 9.8 m/s²
This means that two balls P and Q irrespective of their different masses will come simultaneously to ground because of same accelerations ( 9.8 m/s² ) exerted on them.
F = GMm/R²
And F = mg
mg = GMm/R²
g = GM/R²
For Earth, M = 6 × 10²⁴ and R = 6.4 × 10^6.
g = ( 6.67 × 10^(-11) × 6 × 10²⁴ )/[ 6.4 × 10^6 ]²
g = 9.8 m/s²
This means that two balls P and Q irrespective of their different masses will come simultaneously to ground because of same accelerations ( 9.8 m/s² ) exerted on them.
atul103:
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