Question

two balls S and H , S is thrown with an angle of 45 degree and velocity 30 m/s towards north amd H is thrown with an angle of 15 degree and velocity 20 m/s towards east what will be the displacement between two balls after hitting the ground?

Answer 1

Velocity of ball S is given as

$v_s = 30 m/s @ 45 degree$

now the range at which it will hit the ground is given by

$R = \frac{v^2 sin2\theta}{g}$

now plug in all values in above equation

$R = \frac{30^2* sin(2*45)}{9.8}$

$R_1 = 91.8 m$

now for the other ball speed is given as

$v_H = 20 m/s @ 15 degree$

now the range at which it will hit the ground is given by

$R = \frac{v^2 sin2\theta}{g}$

now plug in all values in above equation

$R = \frac{20^2* sin(2*15)}{9.8}$

$R_2 = 20.4 m$

now the displacement between two balls after it hits on the ground

$d = R_1 - R_2$

$d = 91.8 - 20.4 = 71.4 m$

so the displacement will be 71.4 m