Question

Two balls x and y are thrown from the top of a tower one vertically upwards and other vertically downwards with same speed . Is the time taken by them to reach the ground is 6s and 2s respectively, then height of tower is

Answer 1

ok let height be h

for x

h = ut - 0.5t^2

h = ut - 0.5 × 36

h = ut - 18

for y

h = ut - 0.5t^2

h = ut - 0.5 × 4

h = ut - 2

from both the equation

h = ut - 18

h = ut - 2

h = 20 m

Answer 2

Explanation:

TWO DIGIT NO=10X+Y=Z

X+Y=10Z X=10Z-Y

Y=10Z-X

Let the tower height be z

ATQ

the X reaches ground=6

the y reaches ground=2

6X+2Y=Z

6X+2 (10Z-X)=Z

6X-X+20Z-2X=Z

5X-2X+20Z=Z

3X=Z-20Z

3X=-19Z

3 (10Z-10Z-X)=19Z

30Z-30Z-3X=19Z

3X=19Z

X=19Z/3X