Question

Two bar magnets having same geometry with magnetic moments and and 2m are firstly placed in such a way that there are similar poles are on the same side that its period of oscillation is T1 now the polarity of one of the magnets is reversed the time period of oscillations becomes 32 then​

Answer 1

Answer:

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Answer 2

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Correction in question : If the polarity of one of the magnets is reversed the time period of oscillations becomes 32 then what will be the relation in T1 and T2 ?

S O L U T I O N

The time period of bar magnet is

T = 2 π √ I/MH

Where, M = magnetic moment of magnet

I = moment of inertia

H = horizontal component of magnetic field

When same poles of magnets are placed on same side, then net magnetic moment

M1 = M + 2M = 3 M

∴ T1 = 2π √ I/M1H

T1 = 2π √ I/3MH _[i]

When opposite poles of magnets are placed on same side, then net magnetic moment

M2 = 2M - M = M

∴ T2 = 2π √ I/M2H = 2π√I/MH _[ii]

From Eqs [i] and [ii] we observe that

T1 < T2 !