Question

two bars A and B of circular cross section and of same volume made of same material are subjected to tension. if the diameter of A is half of B and if the force applied to both the rods is same and it is in the elastic limit the ratio of extension of A to that of B will be​

Answer 1

Answer:

Using

Y=△L/LF/A

Y=△L1/L1F/△1−(1)For bar A

Y=△L2/L2F/△2−(2)For bar B

Volume  is  same  for  A  and  B

So,R(2d1)2L1=R(2d2)2L2

d12L1=4d12L2(givend1=21d2)

L2L1=4

Explanation:

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