Question

two batteries having emf 10v,4v respectively there internal resistance are 2ohm and 1 ohm batteries are connected in parallel in such a way that positive terminal of both batteries are connected with 10ohm when negative terminal are connected with 6 ohm midpoint of 10ohm and 6ohm connected with resistance of 4ohm calculate current in each branch nd also find potential across 4ohm
​

Answer 1

Explanation:

Equivalent internal resistance of parallel connection r

eq

=

r

1

+r

2

r

1

r

2

∴ r

eq

=

1+2

1×2

=

3

2

Ω

Equivalent emf of cells in parallel connection E

eq

=[

r

1

E

1

+

r

2

E

2

]r

eq

∴ E

eq

=[

1

2

+

2

4

]×

3

2

=

3

8

V

Potential difference across 10Ω resistor, E=

R+r

eq

R

E

eq

∴ E=

10+

3

2

10

×

3

8

=2.5V

Answer 2

Explanation:

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