Question

Two batteries of 3v and 5v having an internal resistance 1 ohm

Answer 1

5

7

3

1

Answer :

C

Solution :

`E-ir=0`

`:. 3-((3+15)/(1+2+R))(1)=0`

Solving this equation we get

`R=3Omega`

Answer 2

Answer:

first type is first battery added with second battery so 3×5=15 so there answer is 15