Question

Two batteries of emf 4V and 8 V and internal resistance of 1Ω and 2Ω respectively are connected in the circuit with a resistance of 9Ω as shown. The potential difference between A and B is

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Answer 1

Answer:

3 V

Explanation:

Since the batteries are connected in reverse polarities, the net potential applied to the circuit =8V−4V=4V

The net resistance in the circuit =R+r1+r2 =9Ω+1Ω+2Ω=12Ω

The net resistance in the circuit =R+r1+r2 =9Ω+1Ω+2Ω=12ΩHence, the current in the circuit =12Ω4V =31A

The net resistance in the circuit =R+r1+r2 =9Ω+1Ω+2Ω=12ΩHence, the current in the circuit =12Ω4V =31APotential difference across P and Q =IR =31A×9Ω =3V

Answer 2

Answer:

answer is attached

Explanation:

hope it helps you