Question

two batteries of emfs 2V and 1V of internal resistance 1ohm&2ohm respectively are connected in parallel. the effective emf of the combination is

​

Answer 1

The effective emf of the combination =1.67 V

Explanation:

Let

$E_1=2 V$

$E_2=1 V$

$r_1=1\Omega$

$r_2=2\Omega$

When emf are connected in parallel then the effective emf of the combination

$\frac{1}{r}=\frac{1}{r_1}+\frac{1}{r_2}$

Substitute the values

$\frac{1}{r}=1+\frac{1}{2}=\frac{2+1}{2}=\frac{3}{2}$

$r=\frac{2}{3}$

$\frac{E}{r}=\frac{E_1r_2+E_2r_1}{r_1r_2}$

Substitute the values

$E\times \frac{3}{2}=\frac{2\times 2+1\times 1}{2}$

$E=\frac{2}{3}\times \frac{5}{2}=\frac{5}{3}=1.67 V$

Hence, the effective emf of the combination =1.67 V

#Learn more:

https://brainly.in/question/9860196

Answer 2

Answer:

5/3 V

Explanation :